Convert from dBuV
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dBμV with Z = Ω
\(dB\mu V - 60 =\)
dBmV
\(dB\mu V - 120 =\)
dBV
\(dB\mu V-20 \cdot log_{10}(Z)=\)
dBμA
\( dB\mu V-20 \cdot log_{10}(Z)-60= \)
dBmA
\( dB\mu V-20 \cdot log_{10}(Z)-120= \)
dBA
\( dB\mu V-10 \cdot log_{10}(Z)= \)
dBpW
\( dB\mu V-10 \cdot log_{10}(Z)-90= \)
dBm
\( dB\mu V-10 \cdot log_{10}(Z)-120= \)
dBW
\( 10^{dB\mu V/20}= \)
μV
\( 10^{(dB\mu V-60)/20}= \)
mV
\( 10^{(dB\mu V-120)/20}= \)
V
\( 10^{(dB\mu V-20 \cdot log_{10}(Z))/20}= \)
μA
\( 10^{(dB\mu V-20 \cdot log_{10}(Z)-60)/20}= \)
mA
\( 10^{(dB\mu V-20 \cdot log_{10}(Z)-120)/20}= \)
A
\( \frac{(10^{(dB\mu V/20)})^2}{Z}= \)
pW
\( \frac{(10^{(dB\mu V/20)})^2}{Z}\cdot 10^{-9}= \)
mW
\( \frac{(10^{(dB\mu V/20)})^2}{Z}\cdot 10^{-12}= \)
W