Convert from uA

Enter a value for the units below and press calculate.

Convert from
μA with Z = Ω  
 
\( 20 \cdot log_{10}(\mu A) + 20 \cdot log_{10}(Z) = \)
dBμV
\( 20 \cdot log_{10}(\mu A) + 20 \cdot log_{10}(Z) - 60 = \)
dBmV
\( 20 \cdot log_{10}(\mu A) + 20 \cdot log_{10}(Z) - 120 = \)
dBV
\( 20 \cdot log_{10}(\mu A) = \)
dBμA
\( 20 \cdot log_{10}(\mu A) - 60 = \)
dBmA
\( 20 \cdot log_{10}(\mu A) - 120 = \)
dBA
\( 20 \cdot log_{10}(\mu A) + 10 \cdot log_{10}(Z) = \)
dBpW
\( 20 \cdot log_{10}(\mu A) + 10 \cdot log_{10}(Z) - 90 = \)
dBm
\( 20 \cdot log_{10}(\mu A) + 10 \cdot log_{10}(Z) - 120 = \)
dBW
 
\( \mu A \cdot Z = \)
μV
\( \mu A \cdot Z \cdot 10^{-3} = \)
mV
\( \mu A \cdot Z \cdot 10^{-6} = \)
V
\( \mu A \cdot 10^{-3} = \)
mA
\( \mu A \cdot 10^{-6} = \)
A
\( \mu A^2 \cdot Z = \)
pW
\( \mu A^2 \cdot Z \cdot 10^{-9}= \)
mW
\( \mu A^2 \cdot Z \cdot 10^{-12}= \)
W