Convert from dBpW
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dBpW with Z = Ω
\( dBpW + 10 \cdot log_{10}(Z) =\)
dBμV
\( dBpW + 10 \cdot log_{10}(Z) - 60 =\)
dBmV
\( dBpW + 10 \cdot log_{10}(Z) - 120 =\)
dBV
\( dBpW - 10 \cdot log_{10}(Z) =\)
dBμA
\( dBpW - 10 \cdot log_{10}(Z) - 60 =\)
dBmA
\( dBpW - 10 \cdot log_{10}(Z) - 120 =\)
dBA
\( dBpW - 90 = \)
dBm
\( dBpW - 120 = \)
dBW
\( \sqrt{10^{dBpW/10} \cdot Z \cdot 10^{-9} } \cdot 10^6 = \)
μV
\( \sqrt{10^{dBpW/10} \cdot Z \cdot 10^{-9} } \cdot 10^3 = \)
mV
\( \sqrt{10^{dBpW/10} \cdot Z \cdot 10^{-12} } = \)
V
\( \sqrt{ \frac{10^{dBpW/10}} {Z} \cdot 10^{-9} } \cdot 10^6 = \)
μA
\( \sqrt{ \frac{10^{dBpW/10}} {Z} \cdot 10^{-9} } \cdot 10^3 = \)
mA
\( \sqrt{ \frac{10^{dBpW/10}} {Z} \cdot 10^{-12} } = \)
A
\( 10^{dBpW/10} = \)
pW
\( 10^{(dBpW-90)/10} = \)
mW
\( 10^{(dBpW-120)/10} = \)
W